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Re: I can partly show it

Posted by AuntieMel on January 15, 2007, at 12:15:27

In reply to Re: Well, the answer..., posted by linkadge on January 14, 2007, at 13:26:51

We know a and b can't both be even (or the gcd would include 2)

so a^2 is odd if a is odd, even otherwise
and b^2 is odd if b is odd, even otherwise

Odd + even = odd (explains the answer of "1")
odd + odd = even (explains the answer of "2")

also put - (a^2 + b^2(mod 2)) = (a + b(mod2)) which is either 0 or 1

What I can't show is why there aren't any other, higher numbers that can fit.

 

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poster:AuntieMel thread:721428
URL: http://www.dr-bob.org/babble/social/20070112/msgs/722531.html