Posted by Larry Hoover on April 11, 2003, at 9:11:37
In reply to Re: Is my Maths correct? » Larry Hoover, posted by bluedog on April 11, 2003, at 5:23:45
> Hi Larry
> I ended up buying the cheaper of the two substances because the supplier only had a 500g quantity avaialable of the (slightly) less pure substance in my city. However I contacted the companies head office and they assured me that the BP grade I purchased was actually Pharmaceutical grade AND food grade and was in fact pure enough to feed intravenously to hospital patients. The company actually pointed out to me that the BP grade Mag Chlor I was purchasing would in all probability be purer than the tap water I drink each day with regard to trace element contaminants so I felt safe purchasing the BP grade Mag Chlor.
Sounds all right to me, too. <grin>
> If my magnesium trial with the 500g pack works out well for my health and overall vitality, I will then order a 5kg tub of the (slightly) purer product next time round.
If the stuff is IV grade, you can probably save the extra cost.
> Now for my maths...please correct me if I am wrong.
> Firstly To prevent the laxative effect kicking in I wish to start out conservatively and take only 150mg of elemental Mg in each separate dose.
> 1. My 500g tub of MgCL26H20 contains 400x150mg doses of elemental magnesium...Right?????
> Secondly I just so happen to have a 20ml measuring cup at home (came with a cough mixture I once purchased).
Is it just marked at 20 mL, or does it have other graduations?
>So rearranging your formula around I calculate the following:_
> 2. If I dissolve 62.5g of my Mag Chlor in 1000ml of water I will get 150mg of elemental Mg in every 20ml dose....Right????
Yes, but....how do you propose to measure out 62.5 mg?
Alternatively, and using the ratio method, I've calculated that to get 150 mg Mg, from the whole lot dissolved in one litre, you'd need to take 2.5 mL, or 1/2 teaspoon. A baking measure will do fine.
> This is the easiest way I can think of with the resources I currently have at home of getting a fairly accurate 150mg of elemental Mg per dose. (I'm not particularly worried about a few mg more or less each way).
Your method depends on determining the right mass of Mg(Cl)2 in the first place.
> 3. Please correct me if I'm wrong :) :). My maths has definitely slipped over the years...what you don't use you lose...Right?????
That's why we invented calculators, non?
> Thanks Larry